28x^2-43x+9=0

Solution for 28x^2-43x+9=0 equation:

28x^2-43x+9=0

a = 28; b = -43; c = +9;
Δ = b2-4ac
Δ = -432-4·28·9
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-29}{2*28}=\frac{14}{56}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+29}{2*28}=\frac{72}{56}
=1+2/7
$